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[kingofmainframes]

Hi Guys,
I have a requirement to stop executing a job when the number of records in a file is less than 100. Job should end with Return code zero. Please assist.
1) Input file is a VSAM KSDS file - key first 4 bytes.
2) Job has more that 20 steps
3) Record count has to be checked in the first step.

[blitz2]

If writing a Cobol program an option for you, then write a program that counts the number of records in the input file. If they are less than 100, move '1' (or some other number to RETURN-CODE). In the JCL, use condition codes to skip/ continue the rest of the steps based on the condition code. Remember to change the return code to zero in the jcl in case you decide to skip the rest of the steps.
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[prasanth_thavva]

Hi,

One way of checking in JCL is
Use PRINT and Count (100) if it is less than it will return 4 or 8 i am not sure, that way u can execute the step.

Thanks&Regards
Venkata Prasanth

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Thanks&Regards
Prasanth Thavva

[Nic Clouston]

are you saying that EVERY step in the job MUST return a code of 0 or are you saying that the job must not abend? If the first then you cannot. I f the latter then the first response is as good as any - I've just done it for myself except I'm indicating an empty file and doing alternative processing.
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Utility and Program control cards are NOT, repeat NOT, JCL.

[kolusu]

Split the job into 2 jobs. Job1 will have just the 2 steps. In the first step it will check the record count and step2 it will submit the job 2(with all the other steps) or do nothing


JOB 1: