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Problem in SAS\C Double

 
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mrinalsolanki
Beginner


Joined: 02 May 2006
Posts: 56
Topics: 16
PostPosted: Mon Dec 01, 2008 7:31 am    Post subject: Problem in SAS\C Double Reply with quote
Hi All,

I m getting very weird problem and the description is as follows:

Code:
double a;
double b;
double b1;
double b2;
double c;

b=b1+b2;
c=a-b;

if(c < 0.00)
{

do something;
}


Now when i provide a=155.08,b1=127.07,b2=31.01 then c becomes
-0.000000 whereas if a=155.08,b1=127.06,b2=31.02 then c becomes 0.00 . I have never faced this type of issue and it would be of great help if somebody let me know the fix to problem. Thanks in advance.
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mrinalsolanki
Beginner


Joined: 02 May 2006
Posts: 56
Topics: 16
PostPosted: Tue Dec 02, 2008 7:14 am    Post subject: Reply with quote
Hi All,

After lots of investigation it seems to be a problem of Parity Bit.
here are the values which i found in debugger for the above code

Code:
a=4799452345891532308(0x429b147ae147ae14),2FCFCFC(Hex),155.080000(Dec)

b=4799452345891532309(0x429b147ae147ae15),2FCFCFC(Hex),155.080000(Dec)

c=13046928120492326912(0xb510000000000000),2FCFCFC(Hex),-0.000000(Dec)
.

It seems due to difference of -1 in the first value of a and b the whole data is corrupted but how would i check this in my code because i m not been able to understand what is the form of these first values ? Are they representing EBCDIC format or Hex values or something else?

Please send your thoughts.
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